技能叠加 对读条技能有效
define(address,"dnf.exe"+E10B96)
define(bytes,8A 8E 15 08 00 00)
assert(address,bytes)
alloc(newmem,$1000)
alloc(diejia,$1000)
label(code)
label(return)
newmem:
cmp ,00010020
jne @f
jmp code
@@:
mov cl,
mov ,0
jmp return
code:
mov cl,
mov ,cl
mov al,
mov ecx,
mov ,al
movzx ebx,word ptr
mov edx,
mov edx,
push ebx
movzx eax,al
lea ebx,
push ebx
push eax
call edx
inc
cmp dword ptr ,#10//叠加数量
jb code
jmp return
address:
jmp newmem
nop
return:
address:
db bytes
// mov cl,
dealloc(newmem)
{
// ORIGINAL CODE - INJECTION POINT: 01210B96
01210B77: 89 A5 DC F7 FF FF - mov ,esp
01210B7D: 85 D2 - test edx,edx
01210B7F: 74 04 - je 01210B85
01210B81: 8B 12 - mov edx,
01210B83: 89 10 - mov ,edx
01210B85: 89 48 08 - mov ,ecx
01210B88: 8D 85 C4 F7 FF FF - lea eax,
01210B8E: 50 - push eax
01210B8F: 8B CB - mov ecx,ebx
01210B91: E8 5A 57 3C FF - call 005D62F0
// ---------- INJECTING HERE ----------
01210B96: 8A 8E 15 08 00 00 - mov cl,
// ---------- DONE INJECTING----------
01210B9C: 88 8D FA F7 FF FF - mov ,cl
01210BA2: 8A 86 14 08 00 00 - mov al,
01210BA8: 8B 4F 24 - mov ecx,
01210BAB: 88 85 FB F7 FF FF - mov ,al
01210BB1: 0F B7 9E 04 08 00 00- movzx ebx,word ptr
01210BB8: 8B 11 - mov edx,
01210BBA: 8B 52 04 - mov edx,
01210BBD: 53 - push ebx
01210BBE: 0F B6 C0 - movzx eax,al
01210BC1: 8D 5E 04 - lea ebx,
} 哇!这个写哪里!! 6 nb
多重施法
能加个概率吗,赌狗最爱 很多人并不会用这个代码,比如我
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